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5z^2-17z+10=0
a = 5; b = -17; c = +10;
Δ = b2-4ac
Δ = -172-4·5·10
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{89}}{2*5}=\frac{17-\sqrt{89}}{10} $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{89}}{2*5}=\frac{17+\sqrt{89}}{10} $
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